Straight Line Question 104
Question: The distance between the lines $ 3x-2y=1 $ and $ 6x+9=4y $ is [MP PET 1998]
Options:
A) $ \frac{1}{\sqrt{52}} $
B) $ \frac{11}{\sqrt{52}} $
C) $ \frac{4}{\sqrt{13}} $
D) $ \frac{6}{\sqrt{13}} $
Correct Answer: B $ \therefore $ Distance between two lines = $ \frac{|ax_0 + by_0 + c|}{\sqrt{a^2 + b^2}} $ $ \Rightarrow $ $ d=\frac{11}{2\sqrt{13}}=\frac{11}{\sqrt{52}} $ .
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Answer:
Solution:
BETA
