SATHEE: Straight Line Question 115

Straight Line Question 115

Question: The perpendicular distance of the straight line $ 12x+5y=7 $ from the origin is equal to [Pb. CET 2002]

Options:

A) $ \frac{7}{13} $

B) $ \frac{12}{13} $

C) $ \frac{5}{13} $

D) $ \frac{1}{13} $

Show Answer

Answer:

Correct Answer: A

Solution:

Perpendicular distance of straight line $ 12x+5y-7=0 $ from the origin is $ \frac{12\times 0+5\times 0-7}{\sqrt{12^{2}+5^{2}}} $ = $ | \frac{-7}{13} |=\frac{7}{13} $ .

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Straight Line Question 115

Question: The perpendicular distance of the straight line $ 12x+5y=7 $ from the origin is equal to [Pb. CET 2002]

Options:

Answer:

Solution:

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