SATHEE: Straight Line Question 126

Straight Line Question 126

Question: The foot of the coordinates drawn from (2, 4) to the line $ x+y=1 $ is [Roorkee 1995]

Options:

A) $ ( \frac{1}{3},\frac{3}{2} ) $

B) $ ( -\frac{1}{2},\frac{3}{2} ) $

C) $ ( \frac{4}{3},\frac{1}{2} ) $

D) $ ( \frac{3}{4},-\frac{1}{2} ) $

Show Answer

Answer:

Correct Answer: B

Solution:

Applying the formula, the required foot is $ ( \frac{1^{2}\times 2-1\times 1\times 4+1}{1^{2}+1^{2}},\frac{1^{2}\times 4-1\times 1\times 2+1}{1^{2}+1^{2}} )=( -\frac{1}{2},\frac{3}{2} ) $ . Trick: Here, in options only point $ ( -\frac{1}{2},\frac{3}{2} ) $ is satisfying the given equation of line.

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Straight Line Question 126

Question: The foot of the coordinates drawn from (2, 4) to the line $ x+y=1 $ is [Roorkee 1995]

Options:

Answer:

Solution:

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