Straight Line Question 129

Question: If A and B are two points on the line $ 3x+4y+15=0 $ such that $ OA=OB=9 $ units, then the area of the triangle $ OAB $ is

Options:

A)18 sq. units

B) $ 18\sqrt{2}sq. $ units

C)18/ $ \sqrt{2} $ sq. units

D)None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ OA=OB=9,OD=\frac{15}{\sqrt{25}}=3 $ Therefore $ AB=2AD=2\sqrt{81-9}=2\sqrt{72}=12\sqrt{2} $ Hence $ \Delta =\frac{1}{2}(3\times 12\sqrt{2})=18\sqrt{2} $ sq. units.