Straight Line Question 134
Question: The pedal points of a perpendicular drawn from origin on the line $ 3x+4y-5=0 $ , is [RPET 1990]
Options:
A) $ ( \frac{3}{5},2 ) $
B) $ ( \frac{3}{5},\frac{4}{5} ) $
C) $ ( -\frac{3}{5},-\frac{4}{5} ) $
D) $ ( \frac{30}{17},\frac{19}{17} ) $
Correct Answer: B
Show Answer
Answer:
Solution:
Þ $ x=\pm 1.\cos \theta =\pm \frac{3}{5} $ and $ y=\pm 1.\sin \theta =\pm \frac{4}{5} $ Hence $ ( \frac{3}{5},\frac{4}{5} ) $ lies on straight line.
BETA
