Straight Line Question 14

Question: Angle between $ x=2 $ and $ x-3y=6 $ is [MNR 1988]

Options:

A) $ \infty $

B) $ {{\tan }^{-1}}(3) $

C) $ {{\tan }^{-1}}( \frac{1}{3} ) $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ \theta =90^{o}-{{\tan }^{-1}}( \frac{1}{3} ) $ $ \tan \theta =\cot [ {{\tan }^{-1}}( \frac{1}{3} ) ]=3 $

$ \Rightarrow \theta ={{\tan }^{-1}}(3) $ .