Straight Line Question 214

Question: If 2p is the length of perpendicular from the origin to the lines $ \frac{x}{a}+\frac{y}{b}=1 $ , then $ a^{2},8p^{2},b^{2} $ are in

Options:

A) A.P

B) GP.

C) H.P.

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • [c] We have $ 2p| \frac{0+0-1}{\sqrt{\frac{1}{a^{2}}+\frac{1}{b^{2}}}} |\Rightarrow \frac{1}{a^{2}}+\frac{1}{b^{2}}=\frac{1}{4p^{2}} $ $ \frac{1}{a^{2}}+\frac{1}{b^{2}}=\frac{2}{8p^{2}}\Rightarrow \frac{1}{a^{2}},\frac{1}{8p^{2}},\frac{1}{b^{2}} $ are in A.P.
    $ \Rightarrow a^{2},8p^{2},b^{2} $ are in H.P.