Question: If the sum of the distances of a point from two perpendicular lines in a plane is 1, then its locus is
Options:
A) Square
B) Circle
C) Straight line
D) Two intersecting line
Show Answer
Answer:
Correct Answer: A
Solution:
- [a] Let the two perpendicular lines be the coordinate axes and let the point be P(h, k). Then sum of the distances of P(h, k) from the coordinate axes is $ | h |+| k |. $ It is given that $ | h |+| k |=1. $ So, locus of (h, k) is $ | x |+| y |=1. $ this gives four lines $ x+y=1,x-y=1,-x+y=1,-x-y=1 $ which enclose a square.