Straight Line Question 221
Question: A line which makes an acute angle $ \theta $ with the positive direction of x-axis is drawn through the point P(3, 4) to meet the line $ x=6 $ at R and $ y=8 $ at S, then
Options:
A) $ PR=3\cos \theta $
B) $ PS=-4\cos ec\theta $
C) $ PR-PS=\frac{2(3sin\theta +4cos\theta )}{\sin 2\theta } $
D) $ \frac{9}{{{(PR)}^{2}}}+\frac{16}{{{(PS)}^{2}}}=1 $
Correct Answer: D $ \therefore PR=3sec\theta $ Again the point lies on $ y=8 $ if $ 4+r\sin \theta =8 $ $ \therefore r=4\cos ec\theta $ or $ PS=4\cos ec\theta $ other options can be chocked easily
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Answer:
Solution:
BETA
