SATHEE: Straight Line Question 225

Straight Line Question 225

Question: The area of the figure formed by the lines $ ax+by+c=0,ax-by+c=0,ax+by-c=0 $ and $ ax-by-c=0 $ is

Options:

A) $ \frac{c^{2}}{ab} $

B) $ \frac{2c^{2}}{ab} $

C) $ \frac{c^{2}}{2ab} $

D) $ \frac{c^{2}}{4ab} $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Area of triangle $ \Delta AOB=\frac{1}{2}\times \frac{c}{b}\times \frac{c}{a}=\frac{c^{2}}{2ab} $ Total area $ =4\times area\Delta AOB $ $ =4\times \frac{c^{2}}{2ab}=\frac{2c^{2}}{ab} $

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Straight Line Question 225

Question: The area of the figure formed by the lines $ ax+by+c=0,ax-by+c=0,ax+by-c=0 $ and $ ax-by-c=0 $ is

Options:

Answer:

Solution:

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