Straight Line Question 239
Question: D is a point on AC of the triangle with vertices A $ (2,3) $ , $ B(1,-3) $ , $ C(-4,-7) $ and BD divides ABC into two triangles of equal area. The equation of the line drawn though B at right angles to BD is
Options:
A) $ y-2x+5=0 $
B) $ 2y-x+5=0 $
C) $ y+2x-5=0 $
D) $ 2y+x-5=0 $
Correct Answer: A Since, the line BD divides the triangle into two regions of equal area. BD is a median and D is (-1, -2). Slope of $ BD=-\frac{1}{2}. $ So, the required line is $ y+3=-\frac{1}{2}(x-1) $ $ \Rightarrow y-2x+5=0 $
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Answer:
Solution:
BETA
