SATHEE: Straight Line Question 255

Straight Line Question 255

Question: What is the equation of the line which passes through (4, -5) and is perpendicular to $ 3x+4y+5=0? $

Options:

A) $ 4x-3y-31=0 $

B) $ 3x-4y-41=0 $

C) $ 4x+3y-1=0 $

D) $ 3x+4y+8=0 $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ 3x+4y+5=0 $ or $ y=\frac{-3}{4}x+\frac{-5}{4} $ Slope $ =\frac{-3}{4} $ Slope of required line, $ m=\frac{-1}{-\frac{3}{4}}=\frac{4}{3} $ Also line passes through $ (4,-5) $ Equation of line, $ y+5=\frac{4}{3}(x-4) $

$ \Rightarrow 3y+15=4x-16 $

$ \Rightarrow 4x-3y-31=0 $

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Straight Line Question 255

Question: What is the equation of the line which passes through (4, -5) and is perpendicular to $ 3x+4y+5=0? $

Options:

Answer:

Solution:

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