Straight Line Question 284
Question: A line L is perpendicular to the line $ 5x-y=1 $ and the area of the triangle formed by the line L and coordinate axes is 5. The equation of the line L is[IIT 1980; RPET 1997]
Options:
A) $ x+5y=5 $
B) $ x+5y=\pm 5\sqrt{2} $
C) $ x-5y=5 $
D) $ x-5y=5\sqrt{2} $
Correct Answer: BShow Answer
Answer:
Solution:
Þ $ \frac{1}{2}(\lambda )\times ( \frac{\lambda }{5} )=5\Rightarrow \lambda =\pm 5\sqrt{2} $ Hence the equation of required straight line is $ x+5y=\pm 5\sqrt{2} $ .