Straight Line Question 290

Question: The equation of the line passing through the point $ ({x}’,\ {y}’) $ and perpendicular to the line $ y{y}’=2a(x+{x}’) $ is

Options:

A) $ x{y}’+2ay+2a{y}’-{x}’{y}’=0 $

B) $ x{y}’+2ay-2a{y}’-{x}’{y}’=0 $

C) $ x{y}’+2ay+2a{y}’+{x}’{y}’=0 $

D) $ x{y}’+2ay-2a{y}’+{x}’{y}’=0 $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Slope = $ \frac{-{y}’}{2a} $ . Hence equation is $ {y}‘x+2ay={y}’{x}’+2a{y}’ $ .