Straight Line Question 293
Question: The equation of the line perpendicular to the line $ \frac{x}{a}-\frac{y}{b}=1 $ and passing through the point at which it cuts x-axis, is [RPET 1996; Kerala (Engg.) 2002]
Options:
A) $ \frac{x}{a}+\frac{y}{b}+\frac{a}{b}=0 $
B) $ \frac{x}{b}+\frac{y}{a}=\frac{b}{a} $
C) $ \frac{x}{b}+\frac{y}{a}=0 $ $ $
D) $ \frac{x}{b}+\frac{y}{a}=\frac{a}{b} $
Correct Answer: D
Show Answer
Answer:
Solution:
Þ $ k=a^{2} $ . Hence required equation of line is $ ax+by=a^{2} $ i.e., $ \frac{x}{b}+\frac{y}{a}=\frac{a}{b} $ .
BETA
