SATHEE: Straight Line Question 299

Straight Line Question 299

Question: The equation of the line parallel to the line $ 2x-3y=1 $ and passing through the middle point of the line segment joining the points (1, 3) and (1, - 7), is

Options:

A) $ 2x-3y+8=0 $

B) $ 2x-3y=8 $

C) $ 2x-3y+4=0 $

D) $ 2x-3y=4 $

Show Answer

Answer:

Correct Answer: B

Solution:

Midpoint $ \equiv ( \frac{1+1}{2},\frac{3-7}{2} )=(1,-2) $ Therefore required line is $ 2x-3y=k\Rightarrow 2x-3y=8 $ .

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Straight Line Question 299

Question: The equation of the line parallel to the line $ 2x-3y=1 $ and passing through the middle point of the line segment joining the points (1, 3) and (1, - 7), is

Options:

Answer:

Solution:

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