Straight Line Question 303

Question: The equation of a line passing through the point of intersection of the lines $ x+5y+7=0,\ \ 3x+2y-5=0, $ and perpendicular to the line $ 7x+2y-5=0, $ is given by [RPET 1987; MP PET 1993; Pb. CET 2000]

Options:

A) $ 2x-7y-20=0 $

B) $ 2x+7y-20=0 $

C) $ -2x+7y-20=0 $

D) $ 2x+7y+20=0 $

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Answer:

Correct Answer: A

Solution:

  • Point of intersection of the lines is (3, ?2). Hence the equation is $ 2x-7y=2(3)-7(-2)=20 $ .