Straight Line Question 304
Question: A line passes through the point of intersection of $ 2x+y=5 $ and $ x+3y+8=0 $ and parallel to the line $ 3x+4y=7 $ is [RPET 1984; MP PET 1991]
Options:
A) $ 3x+4y+3=0 $
B) $ 3x+4y=0 $
C) $ 4x-3y+3=0 $
D) $ 4x-3y=3 $
Correct Answer: A $ \therefore $ $ 3x+4y=\frac{3(23)+4(-21)}{5}=\frac{69-84}{5}=-3 $ . Hence, required line is $ 3x+4y+3=0 $ .
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Answer:
Solution:
BETA
