SATHEE: Straight Line Question 307

Straight Line Question 307

Question: The equation of a line through $ (3,-4) $ and perpendicular to the line $ 3x+4y=5 $ is [RPET 1981, 84, 86; MP PET 1984]

Options:

A) $ 4x+3y=24 $

B) $ y-4=(x+3) $

C) $ 3y-4x=24 $

D) $ y+4=\frac{4}{3}(x-3) $

Show Answer

Answer:

Correct Answer: D

Solution:

The required equation, which passes through (3, ? 4) and its gradient is $ \frac{4}{3} $ , is $ (y+4)=\frac{4}{3}(x-3) $ .

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Straight Line Question 307

Question: The equation of a line through $ (3,-4) $ and perpendicular to the line $ 3x+4y=5 $ is [RPET 1981, 84, 86; MP PET 1984]

Options:

Answer:

Solution:

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