Straight Line Question 315

Question: The equation of line, which bisect the line joining two points (2, -19) and (6, 1) and perpendicular to the line joining two points (-1, 3) and (5, - 1), is[RPET 1987]

Options:

A) $ 3x-2y=30 $

B) $ 2x-y-3=0 $

C) $ 2x+3y=20 $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

  • Midpoint $ \equiv (4,-9); $ Slope $ =\frac{-1}{\frac{3+1}{-1-5}}=\frac{3}{2} $ Hence the required line is $ 3x-2y=30 $ .