Straight Line Question 318

Question: The equation of line passing through point of intersection of lines $ 3x-2y-1=0 $ and $ x-4y+3=0 $ and the point $ (\pi ,\ 0), $ is [RPET 1987]

Options:

A) $ x-y=\pi $

B) $ x-y=\pi (y+1) $

C) $ x-y=\pi (1-y) $

D) $ x+y=\pi (1-y) $

Show Answer

Answer:

Correct Answer: C

Solution:

  • The point of intersection is (1, 1) Therefore the equation of the line passing through (1, 1) and $ (\pi ,0) $ is $ y-1=\frac{-1}{\pi -1}(x-1)\Rightarrow x-y=\pi (1-y) $ .



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