SATHEE: Straight Line Question 320

Straight Line Question 320

Question: The equation of line passing through the point of intersection of the lines $ 4x-3y-1=0 $ and $ 5x-2y-3=0 $ and parallel to the line $ 2y-3x+2=0, $ is[RPET 1985, 86, 88]

Options:

A) $ x-3y=1 $

B) $ 3x-2y=1 $

C) $ 2x-3y=1 $

D) $ 2x-y=1 $

Show Answer

Answer:

Correct Answer: B

Solution:

The point of intersection of the lines is (1, 1). The equation of line parallel to $ 2y-3x+2=0 $ is $ 2y-3x+k=0 $ . It also passes through (1, 1), therefore $ AC=\sqrt{{{(4-0)}^{2}}+{{( 0-\frac{4}{3} )}^{2}}}=\frac{4\sqrt{10}}{3} $ . Hence the required equation is $ 2y-3x+1=0 $ or $ 3x-2y=1 $ .

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Straight Line Question 320

Question: The equation of line passing through the point of intersection of the lines $ 4x-3y-1=0 $ and $ 5x-2y-3=0 $ and parallel to the line $ 2y-3x+2=0, $ is[RPET 1985, 86, 88]

Options:

Answer:

Solution:

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