Straight Line Question 33
The equation of the bisector of that angle between the lines $ x+2y-11=0 $ , $ 3x-6y-5=0 $ which contains the point (1, -3) is
Options:
A) $ 3x=19 $
B) $ 3y=7 $
C) $ 3x=19 $ and $ 3y=7 $
D) None of these
Correct Answer: A Since the origin and the point (1, -3) lie on the same side of $ x+2y-11=0 $ and on the opposite side of $ 3x-6y-5=0 $ . Therefore, the bisector of the angle containing $ (1,-3) $ is the bisector of that angle which does not contain the origin and is given by $ \frac{-x-2y+11}{\sqrt{5}}=-( \frac{-3x+6y+5}{\sqrt{45}} ) $ i.e., $ x= \frac{19}{3} $ .
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Answer:
Solution:
BETA
