Straight Line Question 344

Question: The equation of the straight line joining the point $ (a,\ b) $ to the point of intersection of the lines $ \frac{x}{a}+\frac{y}{b}=1 $ and $ \frac{x}{b}+\frac{y}{a}=1 $ is

Options:

A) $ a^{2}y-b^{2}x=ab\ (a-b) $

B) $ a^{2}y+b^{2}y=ab\ (a+b) $

C) $ a^{2}y+b^{2}x=ab $

D) $ a^{2}x+b^{2}y=ab\ (a-b) $

Show Answer

Answer:

Correct Answer: A

Solution:

  • The given lines intersect at $ ( \frac{ab}{a+b},\frac{ab}{a+b} ) $ and join of this with (a, b) will have slope $ \frac{b^{2}}{a^{2}} $ . Now proceed.