Straight Line Question 345
Question: The equations of the lines through the origin making an angle of $ 60^{o} $ with the line $ x+y\sqrt{3}+3\sqrt{3}=0 $ are
Options:
A) $ y=0,\ x-y\sqrt{3}=0 $
B) $ x=0,\ x-y\sqrt{3}=0 $
C) $ x=0,\ x+y\sqrt{3}=0 $
D) $ y=0,\ x+y\sqrt{3}=0 $
Correct Answer: B Since the line $ x+y\sqrt{3}+3\sqrt{3}=0 $ makes an angle of $ 150^{o} $ with $ x $ -axis. Therefore, the required lines will make angles of $ 150^{o}+90^{o}=240^{o} $ and $ 150^{o}-90^{o}=60^{o} $ with the positive direction of x-axis. Hence the lines are $ x=0 $ and $ y=\sqrt{3}x $ .
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Answer:
Solution:
BETA
