SATHEE: Straight Line Question 360

Straight Line Question 360

Question: Equation of a line passing through (1, -2) and perpendicular to the line $ 3x-5y+7=0 $ is [RPET 2003]

Options:

A) $ 5x+3y+1=0 $

B) $ 3x+5y+1=0 $

C) $ 5x-3y-1=0 $

D) $ 3x-5y+1=0 $

Show Answer

Answer:

Correct Answer: A

Solution:

Equation of a line perpendicular to $ 3x-5y+7=0 $ is $ 5x+3y+\lambda =0 $ ??(i) $ \because $ This equation passes through $ (1,-2) $ \ $ 5\times 1+3\times (-2)+\lambda =0 $
Þ $ 5-6+\lambda =0 $ Þ $ \lambda =1 $ \ Equation is $ 5x+3y+1=0 $ .

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Straight Line Question 360

Question: Equation of a line passing through (1, -2) and perpendicular to the line $ 3x-5y+7=0 $ is [RPET 2003]

Options:

Answer:

Solution:

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