Straight Line Question 366
Question: One diagonal of a square is along the line $ 8x-15y=0 $ and one of its vertex is (1, 2). Then the equation of the sides of the square passing through this vertex, are [IIT 1962]
Options:
A) $ 23x+7y=9,\ 7x+23y=53 $
B) $ 23x-7y+9=0,\ 7x+23y+53=0 $
C) $ 23x-7y-9=0,\ 7x+23y-53=0 $
D)None of these
Correct Answer: C $ \Rightarrow (15+8m)=\pm (15m-8) $ $ \Rightarrow 23x-7y-9=0 $ and $ y-2=-\frac{7}{23}(x-1) $ $ \Rightarrow 7x+23y-53=0 $ .
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Answer:
Solution:
Þ $ m=\frac{23}{7} $ and $ -\frac{7}{23} $ Hence the equations of DC and AD are $ y-2=\frac{23}{7}(x-1) $
BETA
