Straight Line Question 367

Question: The opposite vertices of a square are (1, 2) and (3, 8), then the equation of a diagonal of the square passing through the point (1, 2), is [Roorkee 1981]

Options:

A) $ 3x-y-1=0 $

B) $ 3y-x-1=0 $

C) $ 3x+y+1=0 $

D)None of these

Show Answer

Answer:

Correct Answer: A

Solution:

  • Slope $ =\frac{8-2}{3-1}=3 $ . The diagonal is $ y-2=3(x-1)\Rightarrow 3x-y-1=0 $ .