Straight Line Question 368
Question: The ends of the base of an isosceles triangle are at $ (2a,\ 0) $ and $ (0,\ a). $ The equation of one side is $ (lx+my)(a+b)=(l+m)\ ab $ The equation of the other side is
Options:
A) $ x+2y-a=0 $
B) $ x+2y=2a $
C) $ 3x+4y-4a=0 $
D) $ 3x-4y+4a=0 $
Correct Answer: D $ \Rightarrow k=\sqrt{4a^{2}+{{(k-a)}^{2}}} $
Þ $ k=\frac{5a}{2} $ Hence the required equation is $ 3x-4y+4a=0 $ .
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Answer:
Solution:
BETA
