Straight Line Question 370
Question: The base BC of a triangle ABC is bisected at the point (p, q) and the equations to the sides AB and AC are respectively $ x+y+3=0 $ and $ qx+py=1. $ Then the equation to the median through A is
Options:
A) $ 2x-y=9 $
B) $ (p^{2}+q^{2}-1)(px+qy-1)=(2p-1)(qx+py-1) $
C) $ (pq-1)(px+qy-1)=(p^{2}+q^{2}-1)(qx+py-1) $
D)None of these
Correct Answer: A
Show Answer
Answer:
Solution:
Þ $ \lambda =-\frac{p^{2}+q^{2}-1}{2pq-1} $ and the equation of median through A is $ (px+qy-1)-\frac{p^{2}+q^{2}-1}{2pq-1}(qx+py-1)=0 $
Þ $ (2pq-1)(px+qy-1)=(p^{2}+q^{2}-1)(qx+py-1) $ .
BETA
