Straight Line Question 376
Question: The vertices of a triangle OBC are $ (0,\ 0),\ (-3,\ -1) $ and $ (-1,\ -3)\ $ respectively. Then the equation of line parallel to BC which is at $ \frac{1}{2} $ unit distant from origin and cuts OB and OC, is [IIT 1976]
Options:
A) $ 2x+2y+\sqrt{2}=0 $
B) $ 2x+2y-\sqrt{2}=0 $
C) $ 2x-2y+\sqrt{2}=0 $
D)None of these
Correct Answer: A
Show Answer
Answer:
Solution:
BETA
