SATHEE: Straight Line Question 387

Straight Line Question 387

Question: The point of intersection of the lines $ \frac{x}{a}+\frac{y}{b}=1 $ and $ \frac{x}{b}+\frac{y}{a}=1 $ lies on the line

Options:

A) $ x-y=0 $

B) $ (x+y)(a+b)=2ab $

C) $ (lx+my)(a+b)=(l+m)\ ab $

D)All of these

Show Answer

Answer:

Correct Answer: D

Solution:

Intersection point of the line is $ ( \frac{ab}{a+b},\frac{ab}{a+b} ) $ , which is satisfying all the equations given in options (a), (b) and (c). Hence (d) is correct.

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Straight Line Question 387

Question: The point of intersection of the lines $ \frac{x}{a}+\frac{y}{b}=1 $ and $ \frac{x}{b}+\frac{y}{a}=1 $ lies on the line

Options:

Answer:

Solution:

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