SATHEE: Straight Line Question 400

Straight Line Question 400

Question: The equation to the line bisecting the join of (3, -4) and (5, 2) and having its intercepts on the x-axis and the y-axis in the ratio 2 : 1 is [Karnataka CET 2005]

Options:

A) $ x+y-3=0 $

B) $ 2x-y=9 $

C) $ x+2y=2 $

D) $ 2x+y=7 $

Show Answer

Answer:

Correct Answer: C

Solution:

Given equation of line having it intercepts on the x- axis and y?axis in the ratio 2:1 i.e., 2a and a \ $ \frac{x}{2a}+\frac{y}{a}=1\Rightarrow x+2y=2a $ ….. (i) According to question, Line (i) also passes through midpoint of $ (3,-4) $ and (5,2) i.e., $ (4,-1) $ . \ $ 4+2(-1)=2a\Rightarrow a=1 $ Hence the equation of required line is, $ x+2y=2 $ .

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Straight Line Question 400

Question: The equation to the line bisecting the join of (3, -4) and (5, 2) and having its intercepts on the x-axis and the y-axis in the ratio 2 : 1 is [Karnataka CET 2005]

Options:

Answer:

Solution:

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