Straight Line Question 51

Question: Three lines $ 3x-y=2,5x+ay=3 $ and $ 2x+y=3 $ are concurrent, then a = [MP PET 1996]

Options:

A)2

B)3

C)-1

D)-2

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ | \begin{matrix} 3 & -1 & -2 \\ 5 & a & -3 \\ 2 & 1 & -3 \\ \end{matrix} |=0 $
    Þ $ 3(-3a+3)+1(-15+6)-2(5-2a)=0 $
    Þ $ a=-2 $ .