SATHEE: Straight Line Question 64

Straight Line Question 64

Question: Let PS be the median of the triangle with vertices $ P(2,\ 2),\ Q(6,\ -\ 1) $ and $ R(7,\ 3) $ . The equation of the line passing through (1,? 1) and parallel to PS is [IIT Screening 2000]

Options:

A) $ 2x-9y-7=0 $

B) $ 2x-9y-11=0 $

C) $ 2x+9y-11=0 $

D) $ 2x+9y+7=0 $

Show Answer

Answer:

Correct Answer: D

Solution:

S = midpoint of $ QR=( \frac{6+7}{2},\frac{-1+3}{2} )=( \frac{13}{2},1 ) $ \ ?m? of $ PS=\frac{2-1}{2-\frac{13}{2}}=-\frac{2}{9} $ , \ The required equation is $ y+1=\frac{-2}{9}(x-1) $ i.e., $ 2x+9y+7=0 $ .

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Straight Line Question 64

Question: Let PS be the median of the triangle with vertices $ P(2,\ 2),\ Q(6,\ -\ 1) $ and $ R(7,\ 3) $ . The equation of the line passing through (1,? 1) and parallel to PS is [IIT Screening 2000]

Options:

Answer:

Solution:

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