Straight Line Question 73

Question: The sides $ AB,BC,CD $ and $ DA $ of a quadrilateral are $ x+2y=3,x=1, $ $ x-3y=4, $ $ 5x+y+12=0 $ respectively. The angle between diagonals $ AC $ and $ BD $ is [Roorkee 1993]

Options:

A) $ 45^{o} $

B) $ 60^{o} $

C) $ 90^{o} $

D) $ 30^{o} $

Show Answer

Answer:

Correct Answer: C

Solution:

  • The four vertices on solving are $ A(-3,3) $ , $ B(1,1), $ $ C(1,-1) $ and $ D(-2,-2) $ . $ m_1 $ = slope of $ AC=-1 $ , $ m_2 $ = slope of $ BD=1 $ ; \ $ m_1m_2=-1 $ . Hence the angle between diagonals AC and BD is $ 90{}^\circ $ .