Straight Line Question 78

Question: A variable line passes through a fixed point P. The algebraic sum of the perpendicular drawn from (2,0), (0, 2) and (1, 1) on the line is zero, then the coordinates of the P are [IIT 1991; AMU 2005]

Options:

A)(1, -1)

B)(1, 1)

C)(2, 1)

D)(2, 2)

Show Answer

Answer:

Correct Answer: B

Solution:

  • Let $ P(x_1,y_1), $ then the equation of line passing through P and whose gradient is m, is $ y-y_1=m(x-x_1) $ Now according to the condition $ \frac{-2m+(mx_1-y_1)}{\sqrt{1+m^{2}}}+\frac{2+(mx_1-y_1)}{\sqrt{1+m^{2}}}+\frac{1-m+(mx_1-y_1)}{\sqrt{1+m^{2}}}=0 $
    Þ $ 3-3m+3mx_1-3y_1=0\Rightarrow y_1-1=m(x_1-1) $ Since it is a variable line, so hold for every value of m. Therefore $ y_1=1,x_1=1\Rightarrow P(1,1) $ .