SATHEE: Straight Line Question 8

Straight Line Question 8

Question: The angle between the lines $ x\cos 30^{o}+y\sin 30{}^\circ =3 $ and $ x\cos 60^{o}+y\sin 60^{o}=5 $ is

Options:

A) $ 90^{o} $

B) $ 30^{o} $

C) $ 60^{o} $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$ \theta ={{\tan }^{-1}}( \frac{-\cot 30^{o}+\cot 60^{o}}{1+\cot 30^{o}\cot 60^{o}} ) $ $ ={{\tan }^{-1}}( \frac{\tan 60^{o}-\tan 30^{o}}{1+\tan 30^{o}\tan 60^{o}} )=30^{o} $ .

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Straight Line Question 8

Question: The angle between the lines $ x\cos 30^{o}+y\sin 30{}^\circ =3 $ and $ x\cos 60^{o}+y\sin 60^{o}=5 $ is

Options:

Answer:

Solution:

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