Straight Line Question 87
Question: The points on the x-axis whose perpendicular distance from the line $ \frac{x}{a}+\frac{y}{b}=1 $ is a, are[RPET 2001; MP PET 2003]
Options:
A) $ [ \frac{a}{b}(b\pm \sqrt{a^{2}+b^{2}}),0 ] $
B) $ [ \frac{b}{a}(b\pm \sqrt{a^{2}+b^{2}}),0 ] $
C) $ [ \frac{a}{b}(a\pm \sqrt{a^{2}+b^{2}}),0 ] $
D)None of these
Correct Answer: A
Show Answer
Answer:
Solution:
Þ $ bh=\pm a\sqrt{a^{2}+b^{2}}+ab\Rightarrow h=\frac{a}{b}(b\pm \sqrt{a^{2}+b^{2}}) $ Hence the point is $ { \frac{a}{b}(b\pm \sqrt{a^{2}+b^{2}}),0 } $ .
BETA
