Straight Line Question 92
Question: If the length of the perpendicular drawn from the origin to the line whose intercepts on the axes are a and b be p, then [Karnataka CET 2003]
Options:
A) $ a^{2}+b^{2}=p^{2} $
B) $ a^{2}+b^{2}=\frac{1}{p^{2}} $
C) $ \frac{1}{a^{2}}+\frac{1}{b^{2}}=\frac{2}{p^{2}} $
D) $ \frac{1}{a^{2}}+\frac{1}{b^{2}}=\frac{1}{p^{2}} $
Correct Answer: D *$ p=\frac{ab}{\sqrt{a^{2}+b^{2}}} $ or $ \frac{a^{2}+b^{2}}{a^{2}b^{2}}=\frac{1}{p^{2}}\Rightarrow \frac{1}{a^{2}}+\frac{1}{b^{2}}=\frac{1}{p^{2}} $ .
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Answer:
Solution:
BETA
