Straight Line Question 98

Question: The distance between $ 4x+3y=11 $ and $ 8x+6y=15 $ , is [AMU 1979; MNR 1987; UPSEAT 2000]

Options:

A) $ \frac{7}{2} $

B)4

C) $ \frac{7}{10} $

D)None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ 4x+3y=11 $ and $ 4x+3y=\frac{15}{2} $ Therefore, $ D=| \frac{11-\frac{15}{2}}{5} |=\frac{7}{10} $ .