Three Dimensional Geometry Question 1
Question: The direction cosines of a line segment $ AB $ are $ -2/\sqrt{17}, $ $ 3/\sqrt{17},-2/\sqrt{17}. $ If $ AB=\sqrt{17} $ and the co-ordinates of A are (3, -6, 10), then the co-ordinates of B are
Options:
A) (1, -2, 4)
B) (2, 5, 8)
C) (-1, 3, -8)
D) (1, -3, 8)
Show Answer
Answer:
Correct Answer: D
Solution:
$ x=3\pm ( \frac{-2}{\sqrt{17}} ),(\sqrt{17}),,y=-,6\pm ( \frac{3}{\sqrt{17}} ),(\sqrt{17}) $
and $ z=10\pm ,( \frac{-2}{\sqrt{17}} ),(\sqrt{17}) $ .
Hence the required co-ordinates are $ (1,,-3,8) $ or $ (5,-9,12) $ .
BETA
