Three Dimensional Geometry Question 115
Question: If the length of perpendicular drawn from origin on a plane is 7 units and its direction ratios are ?3, 2, 6, then that plane is
[MP PET 1998]
Options:
A) $ -3x+2y+6z-7=0 $
B) $ -3x+2y+6z-49=0 $
C) $ 3x-2y+6z+7=0 $
D) $ -3x+2y-6z-49=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
Equation of a plane, when direction ratio and length of perpendicular is given, $ ax+by+cz=p\sqrt{a^{2}+b^{2}+c^{2}} $ Given, $ (a,b,c)\to (-,3,2,6) $ $ -,3x+2y+6z=7,\sqrt{{{(-,3)}^{2}}+2^{2}+6^{2}} $ $ -,3x+2y+6z=49 $ .
BETA
