Three Dimensional Geometry Question 139
Question: The equation of the plane passing through the intersection of the planes $ x+y+z=6 $ and $ 2x+3y+4z+5=0 $ the point (1, 1, 1), is
[AISSE 1983]
Options:
A) $ 20x+23y+26z-69=0 $
B) $ 20x+23y+26z+69=0 $
C) $ 23x+20y+26z-69=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ (x+y+z-6)+\lambda ,(2x+3y+4z+5),=0,\Rightarrow \lambda =\frac{3}{14} $
$ \Rightarrow 20x+23y+26z-69=0 $ .
BETA
