Three Dimensional Geometry Question 140
Question: If the plane $ x-3y+5z=d $ passes through the point (1,2,4), then the lengths of intercepts cut by it on the axes of x, y, z are respectively
[MP PET 1998]
Options:
A) 15, ?5, 3
B) 1, ?5, 3
C) ?15, 5, ?3
D) 1, ?6, 20
Show Answer
Answer:
Correct Answer: A
Solution:
If plane $ x-3y+5z=d $ passes through point (1, 2, 4). Then $ 1-6+20=d\Rightarrow d=15 $
$ \therefore $ Plane, $ x-3y+5z=15 $
$ \Rightarrow \frac{x}{15}+\frac{y}{-5}+\frac{z}{3}=1 $ Hence length of intercept cut by it on the axes (x, y, z) are respectively (15, ? 5, 3).
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