Three Dimensional Geometry Question 154
Question: The equation of the plane which bisects the line joining the points (?1, 2, 3) and (3, ?5, 6) at right angle, is
Options:
A) $ 4x-7y-3z=8 $
B) $ 4x+2y-3z=28 $
C) $ 4x-7y+3z=28 $
D) $ 4x-7y-3z=28 $
Show Answer
Answer:
Correct Answer: C
Solution:
According to question, $ 4x-7y+3z=k $ ?..(i) Also, plane (i) passes through $ ( \frac{-1+3}{2},,\frac{2-5}{2},,\frac{3+6}{2} ) $ , then $ 4+\frac{21}{2}+\frac{27}{2}=k,\Rightarrow k=28 $ Therefore, required equation is $ 4x-7y+3z=28 $ .
BETA
