Three Dimensional Geometry Question 16
Question: The equation to the straight line passing through the points (4, -5, -2) and (-1, 5, 3) is
[MP PET 2003]
Options:
A) $ \frac{x-4}{1}=\frac{y+5}{-2}=\frac{z+2}{-1} $
B) $ \frac{x+1}{1}=\frac{y-5}{2}=\frac{z-3}{-1} $
C) $ \frac{x}{-1}=\frac{y}{5}=\frac{z}{3} $
D) $ \frac{x}{4}=\frac{y}{-5}=\frac{z}{-2} $
Show Answer
Answer:
Correct Answer: A
Solution:
From $ \frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1}=\frac{z-z_1}{z_2-z_1} $ , we get $ \frac{x-4}{1}=\frac{y+5}{-2}=\frac{z+2}{-1} $ , which is the required straight line.
BETA
