Three Dimensional Geometry Question 160
Question: The line $ \frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5} $ is parallel to the plane
[BIT Ranchi 1991; Pb. CET 1991]
Options:
A) $ 3x+4y+5z=7 $
B) $ 2x+y-2z=0 $
C) $ x+y-z=2 $
D) $ 2x+3y+4z=0 $
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Answer:
Correct Answer: B
Solution:
Trick: Since line is parallel to plane if $ al+bm+cn=0 $
$ \therefore $ From option , $ 3,(2)+4(1)+5(-2)=0 $ . Clearly, $ =\sqrt{400+1600+1600}=60km $ is the required plane.
BETA
