Three Dimensional Geometry Question 173
Question: The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is
[CET 1991, 93]
Options:
A) $ x+y+z-15=0 $
B) $ x-y+z-15=0 $
C) $ x-y-z-15=0 $
D) $ x+y+z+15=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
Mid-point of (2,3,4) and (6, 7, 8) is (4, 5, 6). This lies on $ x+y+z-15=0. $ Hence this is the required plane.
BETA
