Three Dimensional Geometry Question 229
Question: The angle between two lines $ \frac{x+1}{2}= $ $ \frac{y+3}{2}=\frac{z-4}{-1} $ and $ \frac{x-4}{1}=\frac{y+4}{2}=\frac{z+1}{2} $ is
[MP PET 1996]
Options:
A) $ {{\cos }^{-1}}( \frac{1}{9} ) $
B) $ {{\cos }^{-1}}( \frac{2}{9} ) $
C) $ {{\cos }^{-1}}( \frac{3}{9} ) $
D) $ {{\cos }^{-1}}( \frac{4}{9} ) $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \theta ={{\cos }^{-1}},( \frac{(2),(1)+(2),(2),+(-1),(2)}{\sqrt{2^{2}+2^{2}+1^{2}}\sqrt{1^{2}+2^{2}+2^{2}}} )={{\cos }^{-1}}\frac{4}{9} $ .
BETA
